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MTH302 Assignment 1 Solution Fall 2021
Question NO 1
Solution
The formula for area is: A=1/2(Base×Height)
Let Suppose the height is fixed and that is 10 meter
now putting the values area changed for 30 S1.m
30= 1/2 (base*10) 30*2=base*10 =60/10=6
Now Putting the value for 35sq.m
35*2=base*10
70/10=7
To find the percentage increase in value the formula is
C=(x_2-x_1)/x_1
C=(7-6)/6 =1/6 =0.16100=16%
The percentage change in the base of the triangle is 16%.
Question NO 2
Solution
First Package
2 Islamic book = 1252 = 250 Reminder Islamic books …..0 2 science book = 1252 = 250
Reminder Science books are 50
2 Geography = 125*2 = 250
Reminder geography books are 20
Let’s Make the 2nd package
2 Islamic book = 752 = 150 Reminder books are : 100 4 Science book = 754 = 300
Reminder books are: 0
1 Geography Book = 75*1 = 75
Reminder books are: 195
Let’s make the 3rd package
3 Islamic book are = 543 = 250 Reminder books : 88 4 Science book are = 544 = 216
Reminder books are : 84
5 Geography books are = 54 * 5 = 270
Reminder books are: 0
Now how many packs should be made to maximize the book fair:
125 for first package
75 for 2nd package
54 for 3rd package
What will be the profit now?
By multiplying the package by the given prices
120125 = 15000 10075 = 7500
270*54 = 14580
Question NO 3
Solution
Series discount of 3%, 5%, and 7%
The formula for series discount is quite simple
Net price = L*1(1-d_1 )(1-d_2 )(1-d_3 )
List Price = 16,000,000
N = 16,000,000 * 1 (1-3%)(1-5%)(1-7%)
The formula for series discount is quite simple
Net Price = 16,000,000
N=16,000,0001(1-3%)(1-5%)(1-7%) N=16,000,0001(1-0.03)(1-0.05)(1-0.07)
N=16,000,0001(0.97)(0.95)(0.93) N=16,000,0000.856995
N=13,71,192
Deal 2: A Cash Discount of 15/10 (i.e. 15% discount if payment is made in the first 10 days).
the formula for cash discount is
N=L(1-d)
N=16,000,000(1-15%)
N=16,000,000(0.85)
N=13,60,000
The deal No 1 is: N=13,71,192
The deal no 2 is: N=13,60,000
So as a buyer, we will be in more benefits if we buy the 2nd deal.
MTH302 Assignment 1 Solution Fall 2021
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